The van der waal’s equation of state for 1 mole of gas is (P + a/V2)

1.	The van der waal’s equation of state for 1 mole of gas is (P + a/V2)(V - b) = RTArrange the following gases in order of increasing value of ‘a’. The gases are CO2, H2, He and N2. How does the value of V related to the ease of liquifaction?
Answer» H₂ < He < N₂ < CO₂ is the order of increasing value of ‘a’. Measure of ‘a’ is proportional to the amount of force of intermolecular attraction. CO₂ molecule being larger in size, has higher magnitude of van der Waal’s force of attraction and hence highest value of ‘a’. Also, higher is the intermolecular force of attraction, easier it is to liquefy a gas ie., higher the value of ‘a’, higher will be the case of liquefaction.

The van der waal’s equation of state for 1 mole of gas is (P + a/V2)(V - b) = RTArrange the following gases in order of increasing value of ‘a’. The gases are CO2, H2, He and N2. How does the value of V related to the ease of liquifaction?

Answer»

H₂ < He < N₂ < CO₂ is the order of increasing value of ‘a’. Measure of ‘a’ is proportional to the amount of force of intermolecular attraction. CO₂ molecule being larger in size, has higher magnitude of van der Waal’s force of attraction and hence highest value of ‘a’.

Also, higher is the intermolecular force of attraction, easier it is to liquefy a gas ie., higher the value of ‘a’, higher will be the case of liquefaction.

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The van der waal’s equation of state for 1 mole of gas is (P + a/V2)(V - b) = RTArrange the following gases in order of increasing value of ‘a’. The gases are CO2, H2, He and N2. How does the value of V related to the ease of liquifaction?

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