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the velocity of a particle falling freely from a height h is given by v is equal to under root 2gh examine the dimensional balance of the equation where the is acceleration due to gravity |
| Answer» TION:v 2 −u 2 =2gxv=18 kmphg=1000 cm/s 2 x=120 cmWe need to BRING all UNITS in CGS units.So, v=18 KMPH= 60×6018×10 5 seccm =(500) cm/secu 2 =v 2 −2gx =(500) 2 −2×1000×120 =250000−240000u 2 =10000 (cm/sec) 2 u=100 cm/secu=1 m/sechope it's helpfulthank you | |