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the velocity of a particle falling freely from a height h is given by v is equal to under root 2gh examine the dimensional balance of the equation where the is acceleration due to gravity |
Answer» <html><body><a href="https://interviewquestions.tuteehub.com/tag/tion-1420808" style="font-weight:bold;" target="_blank" title="Click to know more about TION">TION</a>:v 2 −u 2 =2gxv=18 kmphg=1000 cm/s 2 x=120 cmWe need to <a href="https://interviewquestions.tuteehub.com/tag/bring-402271" style="font-weight:bold;" target="_blank" title="Click to know more about BRING">BRING</a> all <a href="https://interviewquestions.tuteehub.com/tag/units-1438468" style="font-weight:bold;" target="_blank" title="Click to know more about UNITS">UNITS</a> in CGS units.So, v=18 <a href="https://interviewquestions.tuteehub.com/tag/kmph-533998" style="font-weight:bold;" target="_blank" title="Click to know more about KMPH">KMPH</a>= 60×6018×10 5 seccm =(500) cm/secu 2 =v 2 −2gx =(500) 2 −2×1000×120 =250000−240000u 2 =<a href="https://interviewquestions.tuteehub.com/tag/10000-265645" style="font-weight:bold;" target="_blank" title="Click to know more about 10000">10000</a> (cm/sec) 2 u=100 cm/secu=1 m/sechope it's helpfulthank you</body></html> | |