The velocity of a particle is given by `v=u_(0) + g t+ 1/2 at^(2)`. If its position is `x =0` at `t=0`, then what is its displacement after `t=1 s` ?

The velocity of a particle is given by `v=u_(0) + g t+ 1/2 at^(2)`. If

1.	The velocity of a particle is given by `v=u_(0) + g t+ 1/2 at^(2)`. If its position is `x =0` at `t=0`, then what is its displacement after `t=1 s` ?
Answer» Here, `v=(dx) /(dt) v_(0) + gt +1/2 ft^(2)` or `dx =(v_(0) + gt +1/2 ft^(2) ) dt` Integration it the conditions of motion, i.e. as (t) changes 0 to `1 s`, (x) changes `o to x`, we get `int _(0)^(x) dx =int _(0)^(1) (v_(0) + gt + 1/2 ft^(2) ) dt` `x=v_(0) (t) _(0)^(1) +g (t^(2)/2)_(0)^(1) + 1/2 (t^(3)/3)_(0)^(1)` `=v_(0) + g/2 +f/6`.

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The velocity of a particle is given by `v=u_(0) + g t+ 1/2 at^(2)`. If its position is `x =0` at `t=0`, then what is its displacement after `t=1 s` ?

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