The velocity of a particle of mass 10^(-2)kg is given as vecv=(2xhatu+3yhatj+4zhatk) m/sec (where x, y and z are in meter). The amount of work done by applied force in displacing a particle from (1m, 2m, 0) to (-1m, 3m, 1m) is …..

The velocity of a particle of mass 10^(-2)kg is given as vecv=(2xhatu+

1.	The velocity of a particle of mass 10^(-2)kg is given as vecv=(2xhatu+3yhatj+4zhatk) m/sec (where x, y and z are in meter). The amount of work done by applied force in displacing a particle from (1m, 2m, 0) to (-1m, 3m, 1m) is …..
Answer» <html><body><p>0.31 joule<br/>0.24 joule<br/>0.48 joul<br/>0.72 joule</p>Answer :A</body></html>