Saved Bookmarks
| 1. |
The velocity of a particle of mass 10^(-2)kg is given as vecv=(2xhatu+3yhatj+4zhatk) m/sec (where x, y and z are in meter). The amount of work done by applied force in displacing a particle from (1m, 2m, 0) to (-1m, 3m, 1m) is ….. |
|
Answer» 0.31 joule |
|