1.

The velocity of a particle of mass 10^(-2)kg is given as vecv=(2xhatu+3yhatj+4zhatk) m/sec (where x, y and z are in meter). The amount of work done by applied force in displacing a particle from (1m, 2m, 0) to (-1m, 3m, 1m) is …..

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0.31 joule
0.24 joule
0.48 joul
0.72 joule

Answer :A


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