The velocity-time graph for an object is shown in the following figure

1.	The velocity-time graph for an object is shown in the following figure:1. State the type of motion that the graph represents.2. What does the slope of the graph represent?3. What does the area under graph represent?4. Calculate the distance travelled by the object in 15 s.
Answer» (1) Uniformly accelerated motion, since the slope of the velocity-time graph is positive and uniform. (2) It represents acceleration. (3) The area below the velocity-time graph and time axis represents the distance covered. (4) The area covered in 15 s i.e., area of triangle OBC gives the distance covered in 15 s. ∴ Distance covered = \(\frac{1}{2}\) x BC x OC = \(\frac{1}{2}\) x 30 x 15 Distance = 225 m.

The velocity-time graph for an object is shown in the following figure:1. State the type of motion that the graph represents.2. What does the slope of the graph represent?3. What does the area under graph represent?4. Calculate the distance travelled by the object in 15 s.

Answer»

(1) Uniformly accelerated motion, since the slope of the velocity-time graph is positive and uniform.

(2) It represents acceleration.

(3) The area below the velocity-time graph and time axis represents the distance covered.

(4) The area covered in 15 s i.e., area of triangle OBC gives the distance covered in 15 s.

∴ Distance covered

= \(\frac{1}{2}\) x BC x OC

= \(\frac{1}{2}\) x 30 x 15 Distance

= 225 m.