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The velocity `upsilon` of a particle as a function of its position (x) is expressed as `upsilon = sqrt(c_(1)-c_(2)x)`, where `c_(1)` and `c_(2)` are positive constants. The acceleration of the particle isA. `c_(2)`B. `-(c_(2))/(2)`C. `c_(1)-c_(2)`D. `(c_(1)+c_(2))/(2)` |
Answer» Correct Answer - B `upsilon^(2)=c_(1)-c_(2)x` comparing wiuth `upsilon^(2)=u^(2)+2as` we have `a=-(c_(2))/(2)` |
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