The vibration of air in an open organ pipe of length 30 cm is represented by Δp=8sin(2πx25)cos(48πt), where x, p and t are in cm,N/m2 and sec respectively. The excess pressure (pressure over atmospheric pressure) amplitude at x=10 cm is[ Take sin(4π5)=0.587 ]

The vibration of air in an open organ pipe of length 30 cm is represen

1.	The vibration of air in an open organ pipe of length 30 cm is represented by Δp=8sin(2πx25)cos(48πt), where x, p and t are in cm,N/m2 and sec respectively. The excess pressure (pressure over atmospheric pressure) amplitude at x=10 cm is[ Take sin(4π5)=0.587 ]
Answer» The vibration of air in an open organ pipe of length $30 cm$ is represented by $Δ p = 8 sin (\frac{2 π x}{25}) cos (48 π t),$ where $x, p and t$ are in $cm, {N/m}^{2}$ and $sec$ respectively. The excess pressure (pressure over atmospheric pressure) amplitude at $x = 10 cm$ is [ Take $sin (\frac{4 π}{5}) = 0.587$ ]

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The vibration of air in an open organ pipe of length 30 cm is represented by Δp=8sin(2πx25)cos(48πt), where x, p and t are in cm,N/m2 and sec respectively. The excess pressure (pressure over atmospheric pressure) amplitude at x=10 cm is[ Take sin(4π5)=0.587 ]

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