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The voltage across a wire is (100pm5)V and the current passing through it is (10pm0.2) A. Find the resistance of the wire.

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/voltage-1447811" style="font-weight:bold;" target="_blank" title="Click to know more about VOLTAGE">VOLTAGE</a> `V = (100 pm 5) V` <br/> Current I = (10 pm 0.2) A` <br/> Resistance R = ? <br/> Then resistance R is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by Ohm.s law R = V/I = 100/10 = 10 <a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a> ` <br/>` (Delta R)/(R ) = ( (<a href="https://interviewquestions.tuteehub.com/tag/deltav-2053504" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAV">DELTAV</a>)/(V) + (Delta I)/(I) )` <br/>`Delta R = ((Delta V)/(V) + (Delta I)/(I) R= (5/100 + (0.2)/(10) ) 10` <br/>` = (0.05 + 0.02)10 = 0.07 xx 10 = 0.7` <br/> The resistance ` R = (10 pm 0.7) rho `</body></html>


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