The volume of the air bubble increases by 10%, when it rises from bottom to the surface of the water pond. If the temperature of the water is constant, find the depth of the pond. ( 1 atm = 10 m of water column)

The volume of the air bubble increases by 10%, when it rises from bott

1.	The volume of the air bubble increases by 10%, when it rises from bottom to the surface of the water pond. If the temperature of the water is constant, find the depth of the pond. ( 1 atm = 10 m of water column)
Answer» SOLUTION :Volume of the air bubble at the bottom of the POND `(V_(1) ) = V` Volume of the air bubble at the surface of the pond`V_(2) = V xx (110)/(100)` Pressure at the bottom of the pond `(P_(1) )` = (H+ H) cm of water column Where .h. is the DEPTH of the pond and .H. is the atmospheric pressure pressure on surface of the pond `(P_(2)) = H ` cm of water column From Boyle.s law, `P_(1) V_(1) = P_(2) V_(2) ` or `(h + H) V = H (V xx (110)/(100) ) , "" h + H = H xx (110)/(100)` h = `H xx (110)/(100) - H = H xx (10)/(100) = (H)/(10)` `therefore` Depth of the pond = H/10 cm `= (1000)/(10) = 100 ` cm = 1m