1.

The volume (V) of a moatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is

Answer» <html><body><p>`(2)/(5)`<br/>`(2)/(3)`<br/>`(1)/(3)`<br/>`(2)/(7)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> process is isobaric. <br/> `:. dQ = nC_(P)dT`, where `C_(P)` is <a href="https://interviewquestions.tuteehub.com/tag/specific-1220917" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIFIC">SPECIFIC</a> heat at constant pressure. <br/> or `dQ = n((5)/(2)R)dT` Also, `<a href="https://interviewquestions.tuteehub.com/tag/dw-943287" style="font-weight:bold;" target="_blank" title="Click to know more about DW">DW</a> = PdV = nRdT (because PV = <a href="https://interviewquestions.tuteehub.com/tag/nrt-1109890" style="font-weight:bold;" target="_blank" title="Click to know more about NRT">NRT</a>)` <br/> Required <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> = `(dW)/(dQ) = ((nRdT)/(n(5)/(2)R)dT) = (2)/(5)`</body></html>


Discussion

No Comment Found