The volume (V) of a moatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is

The volume (V) of a moatomic gas varies with its temperature (T), as s

1.	The volume (V) of a moatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is
Answer» `(2)/(5)` `(2)/(3)` `(1)/(3)` `(2)/(7)` Solution :GIVEN process is isobaric. `:. dQ = nC_(P)dT`, where `C_(P)` is SPECIFIC heat at constant pressure. or `dQ = n((5)/(2)R)dT` Also, `DW = PdV = nRdT (because PV = NRT)` Required RATIO = `(dW)/(dQ) = ((nRdT)/(n(5)/(2)R)dT) = (2)/(5)`