The work done in time t on a body of mass m which is accelerated from rest to a speed v in time t_1 as a function of time t is given by

The work done in time t on a body of mass m which is accelerated from

1.	The work done in time t on a body of mass m which is accelerated from rest to a speed v in time t_1 as a function of time t is given by
Answer» <html><body><p>`1/2 m (v)/(t_1) t^2`<br/>`m v/(t_1)t^2`<br/>`1/2 ((<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>)/(t_1))^(2) t^2`<br/>`1/2 m (v^2)/(t_1^2) t^2`</p>Solution :As `v =u + at = 0 + at_1 "" ( :. u = 0)` <br/> `:. A = (v)/(t_1) "" ….(i)` <br/> Force, `F = ma = (mv)/(t_1) ` <br/> <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> travelled by the body in time t is <br/> `s = <a href="https://interviewquestions.tuteehub.com/tag/ut-718961" style="font-weight:bold;" target="_blank" title="Click to know more about UT">UT</a> + 1/2 at^2 = 0 + 1/2 (vt^2)/(t_1) = (vt^2)/(2t_1) "(Using (i))"` <br/> `:. <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> = F xx s = (mv)/(t_1) (vt^2)/(2t_1) = 1/2 (mv^2 t^2)/(t_1^2)`</body></html>