1.

There are n white and n black balls marked 1,2,3,………..n. The number of ways in which we can arrange theseballs in a row so that neighbouring balls are of different colours are:

Answer»

`N!`
`(2N)!`
`2(n!)^(2)`
`((2n)!)/((n!)^(2))`

Solution :CASE I:
`(W_(1))/1(B_(1))/2 (W_(2))/3 (B_(2))/4 (W_(3))/5 (B_(3))/6…………W_(n)(B_(n))/(2n^(th)"place")=n!xx!`
CaseII
`(B_(1))/1 (W_(1))/2(B_(2))/3(W_(2))/4(B_(3))/5 (W_(3))/6……….B_(n)(W_(n))/(2n^(th)"place")=n!xxn!`
Son number of ways `=2(n!)^(2)`


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