There are three bags, the first bag contains 3 red ball, 3 white ball and 2 black balls, the second bag contains 2 red ball, 3 white ball and 3 Black balls, the third bag contains 4 red, 3 white and 1 black balls. A person draw randomnly three balls from any of the bag, find the probability of getting. 1) All three balls are of same colour. 2) All three balls are of different colour. 3) Two balls are of same colour and one is different

There are three bags, the first bag contains 3 red ball, 3 white ball

1.	There are three bags, the first bag contains 3 red ball, 3 white ball and 2 black balls, the second bag contains 2 red ball, 3 white ball and 3 Black balls, the third bag contains 4 red, 3 white and 1 black balls. A person draw randomnly three balls from any of the bag, find the probability of getting. 1) All three balls are of same colour. 2) All three balls are of different colour. 3) Two balls are of same colour and one is different
Answer» <html><body><p>5/28Step-by-step explanation:<a href="https://interviewquestions.tuteehub.com/tag/probability-13327" style="font-weight:bold;" target="_blank" title="Click to know more about PROBABILITY">PROBABILITY</a> of not getting <a href="https://interviewquestions.tuteehub.com/tag/red-613739" style="font-weight:bold;" target="_blank" title="Click to know more about RED">RED</a> <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> in first draw = 8/6Probability of not getting red ball in <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> draw = 5/7And probability of getting red ball in third draw = 6/2Hence required probability = 8/6 × 7/5× 6/2 = 5/28Hope It Helps !!!</p></body></html>

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