1.

There is a long narrow and smooth groove in a horizontal table. Two identical blocks A and B each of mass m are placed inside the groove at some separation. An ideal spring is fixed to A as shown. Block A is given a velocity `u` to the right and it interacts with B through the spring. (a) What will be final state of motion of the two blocks ? (b) During their course of interaction what is the minimum kinetic energy of the system ? (c) The spring is removed and the two blocks are tied using a mass less string. Now A is set into motion with speed `u`. What will be the final state of motion of the two blocks in this case ? How much kinetic energy is lost by the system ? Where goes this energy ?

Answer» Correct Answer - (a) A will be at rest and B will have a velocity u
(b) `(m u^(2))/(4)`
(c) Both will be travelling with velocity `(u)/(2)`. Loss in `KE=(m u^(2))/(4)`


Discussion

No Comment Found

Related InterviewSolutions