InterviewSolution
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InterviewSolution
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There is a salt of weak acid and weak base the `K_(a)` of the acid is greater than the `K_(b)` of the base henceA. Degree of hydrolysis is independent of the concentration of the salt solutionB. Anionic hydrolysis will be greater than cationic hydrolysisC. Cationic hydrolysis is greater than anionic hydrolysisD. `h = sqrt((K_(w))/(K_(a)K_(b)))` |
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Answer» Correct Answer - A::C::D Foa a salt of weak acid and weak base `K_(h) = (K_(w))/(K_(a)K_(b)) = ([HA][BOH])/([A^(-)][B^(+)]` and `h = sqrt((K_(w))/(K_(a)K_(b)))` Hence degree of hydrolysis is independent of the concentration of the salt taken. `{:("Further",A^(-)+H_(2)O hArr HA+OH^(-),,....(i)),(,B^(+)+H_(2)O hArr BOH + H^(+),,...(ii)):}` Since `K_(a)` of HA is more than `K_(b)` of BOH so the extent of backward reaction in (i) is greater than the extent of of hydrolysis of `B^(+)` Hence choices (a), (c) and (d) are correct while (b) is incorrect. |
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