Three forces bar(F_(1)), bar(F_(2)) and bar(F_(3)) are simultaneously acting on a particle of mass 'm' and keep it in equilibrium. If bar(F_(1)) force is reversed in direction only, the acceleration of the particle will be.

Three forces bar(F_(1)), bar(F_(2)) and bar(F_(3)) are simultaneously

1.	Three forces bar(F_(1)), bar(F_(2)) and bar(F_(3)) are simultaneously acting on a particle of mass 'm' and keep it in equilibrium. If bar(F_(1)) force is reversed in direction only, the acceleration of the particle will be.
Answer» <html><body><p>`bar(F_(1))//m`<br/>`2bar(F_(1))//m`<br/>`-bar(F_(1))//m`<br/>`-2bar(F_(1))//m`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Under equilibrium condition `<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(F_(1))+vec(F_(2))+vec(F_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>` <br/> `vec(F_(1))=-(F_(1)+F_(2)), a=(-F_(1)+F_(2)+F_(3))/(m)`</body></html>