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    				| 1. | Three moles of oxygen ar mixed with two moles of helium. What will be the ratio of specific heats at constant pressure and constant volume for the mixture ?A. `2.5`B. `3.5`C. `1.5`D. 1 | 
| Answer» Correct Answer - C For a monatomic gas like helium `gamma_(He)=5/3` For a diatomic gas like oxygen `gamma_(O_(2))=7/5` `therefore gamma_(mix)=(3xxgamma_(O_(2))+2xxgamma_(He))/((3+2))` `=(3xx7/5+2xx5/3)/(5)=(21/5+10/3)/(5)=(113)/(15xx5)=1.5` | |