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Three moles of oxygen ar mixed with two moles of helium. What will be the ratio of specific heats at constant pressure and constant volume for the mixture ?A. `2.5`B. `3.5`C. `1.5`D. 1

Answer» Correct Answer - C
For a monatomic gas like helium `gamma_(He)=5/3`
For a diatomic gas like oxygen `gamma_(O_(2))=7/5`
`therefore gamma_(mix)=(3xxgamma_(O_(2))+2xxgamma_(He))/((3+2))`
`=(3xx7/5+2xx5/3)/(5)=(21/5+10/3)/(5)=(113)/(15xx5)=1.5`


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