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Three particles of identical masses .m. are kept at the vertices of an equilateral triangle of each side length.a.. Find the gravitational force of attraction on any one of the particles.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : Let `F_A` and `F_B` be the forces due to the <a href="https://interviewquestions.tuteehub.com/tag/masses-1088822" style="font-weight:bold;" target="_blank" title="Click to know more about MASSES">MASSES</a> at A and B on the mass at <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>. <br/>Here `F_A=F_B` <br/>Hence the Resultant <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> on the mass at C <br/> `F=2F_A cos theta//<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> =2. (Gm^2)/a^2 cos 30^@` <br/> `=2xx(Gm^2)/a^2xxsqrt3/2 = sqrt3(Gm^2)/a^2` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_B_C09_SLV_011_S01.png" width="80%"/></body></html>


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