Three particles of masses `20g`, `30g` and `40g` are initially moving along the positive direction of the three coordinate axes respectively with the same velocity of `20cm//s`. When due to their mutual interaction, the first particle comes to rest, the second acquires a velocity `(10hati+20hatk)cm//s`. What is then the velocity of the third particle?

Three particles of masses `20g`, `30g` and `40g` are initially moving

1.	Three particles of masses `20g`, `30g` and `40g` are initially moving along the positive direction of the three coordinate axes respectively with the same velocity of `20cm//s`. When due to their mutual interaction, the first particle comes to rest, the second acquires a velocity `(10hati+20hatk)cm//s`. What is then the velocity of the third particle?
Answer» Correct Answer - A::B::C `p_i=p_f` `:. (20)(20hati)+30(20hatj)+40(20hatk)` `=(20)(0)+30(10hati+20hatk)+40v` Solving this equation we get, `v=(2.5hati+15hatj+5hatk)cm//s`

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