InterviewSolution
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InterviewSolution
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Three reactions involving `H_(2)PO_(4)^(-)` are given below `I. H_(3)PO_(4)+H_(2)OrarrH_(3)O^(+)+H_(2)PO_(4)^(-)` `II. H_(2)PO_(4)^(-)+H_(2)OrarrHPO_(4)^(2-)+H_(3)O^(+)` `III. H_(2)PO_(4)^(-)+OH^(-)rarrH_(3)PO_(4)+O^(2+)` In which of the above does `H_(2)PO_(4)^(-)` act as an acid?A. (ii) onlyB. (i) and (ii)C. (iii) onlyD. (i) only |
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Answer» Correct Answer - A (i) `{:(H_(3)PO_(4)+H_(2)OhArrH_(3)O^(+)+,H_(2)PO_(4)^(-)),("acid","conjugate base"):}` In reverse reaction `H_(2)PO_(4)^(-)` is accepting a proton, so it base. (ii) `{:(H_(2)PO_(4)^(-)+H_(2)OhArr,HPO_(4)^(2-),+H_(3)O^(+)),("acid","conjugate base",):}` `H_(2)PO_(4)^(-)` is donating a proton, which is accepting by `H_(2)O`, so it is an acid. (iii) `{:(H_(2)PO_(4)^(-)+,OH^(-)hArr,H_(3)PO_(4),+O^(2-)),("acid","acid",conjugate base",):}` `H_(2)PO_(4)^(-)` is a accepting a proton, so it is base. Only in reaction (ii) `H_(2)PO_(4)^(-)` acids as an acid. |
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