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Three spherical balls of masses 1kg, 2kg and 3kg are placed at the corners of an equilateral triangle of side 1m. Find the magnitude of the gravitational force experted by the 2kg and 3kg masses on the 1kg mass.

Answer» <html><body><p></p>Solution :Mass of the spherical ball at the corner .A. of the equilateral triangle = 1kg<br/>Mass of the spherical ball at the corner .B. of the equilateral triangle = 2kg<br/>Mass of the spherical ball at the comer .C. of the equilateral triangle = 3kg<br/> Side of equilateral triangle = 1m<br/>If .<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>. is the force of attraction between 1kg, 2kg masses then<br/>`F_1 = G <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> (1 xx 2)/((1)^2) rArr F_1 = 2G` <br/>If `.F_2.` is the force of attraction between 1kg, 3kg masses then<br/>` F_2 = G xx (1xx3)/((1)^2) rArr F_2 = 3G`<br/> The <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> between the forces `F_1` and `F_2`is `<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^@`. If `.F_R.`is the resultant of these two forces, then according to parallelogram law of <a href="https://interviewquestions.tuteehub.com/tag/vectors-14090" style="font-weight:bold;" target="_blank" title="Click to know more about VECTORS">VECTORS</a> we can write<br/>`F_R = sqrt(F_1^2 + F_2^2 +2F_1F_2 Cos theta ) rArr F_R = sqrt((2G)^2 + (3G)^2 +2 xx 2G xx 3G xx cos 60^@) rArr F_R = sqrt19 G`</body></html>


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