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Time for 20 oscillations of a pendulum is measured as t_(1)= 39.6 s, t_(2) = 39.9 s and t_(3) = 39.5 s. What is the precision in the measurements ? What is the accuracy of the measurement ?

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> `t_(1)=39.6s t_(2)=39.9 s and t_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)=39.5 s` <br/> Least count of measuring instrument = 0.1 s (As measurements have only one significant <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a> after decimal <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a>) <br/> Precision in the measurement = Least count of the instrument = 0.1 s <br/><br/> Average time for 20 oscillations is given by <br/> `t=(t_(1)+t_(2)+t_(3))/(3)` <br/> `=(329.6+39.9+39.5)/(3)=39.7 s` <br/> Absolute errors in the measurements <br/> `Deltat_(1)=t-t_(2)=39.7-39.6-39.6=0.1s ` <br/> `Deltat_(2)=t-t_(2)=39.7-39.39.5 = 0.2 s` <br/> Average absolute error `=(|Deltat_(1)|+|Deltat_(2)|+|Deltat_(3)|)/(3)` <br/> `=(0.1+0.2+0.2)/(3)` <br/> `=(0.5)/(3)=0.17~~0.2` <br/> (rounding off upto one decimal place) <br/> `:.` Accuracy of measurement `=+-0.2s`</body></html>


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