To simulate car accidents, auto manufactures study the collisions of moving cars with mounted springs of different spring constants. Consider a typical simulation with a car of mass 1000 kg moving with a speed 18.0 km/h on a smooth road and coliding 6.25 xx 10^(3) N m^(-1). What is the maximum compression of the spring ?

To simulate car accidents, auto manufactures study the collisions of m

1.	To simulate car accidents, auto manufactures study the collisions of moving cars with mounted springs of different spring constants. Consider a typical simulation with a car of mass 1000 kg moving with a speed 18.0 km/h on a smooth road and coliding 6.25 xx 10^(3) N m^(-1). What is the maximum compression of the spring ?
Answer» <html><body><p></p>Solution :At <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> <a href="https://interviewquestions.tuteehub.com/tag/compression-20610" style="font-weight:bold;" target="_blank" title="Click to know more about COMPRESSION">COMPRESSION</a> `x_(m)`, the potentia energy V of the spring is equal to the kinetic K of the <a href="https://interviewquestions.tuteehub.com/tag/moving-548882" style="font-weight:bold;" target="_blank" title="Click to know more about MOVING">MOVING</a> car from the principle of conservation of <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> energy. <br/> `K=UrArr(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)mu^(2)=(1)/(2)kx_(m)^(2)rArrx_(m)=usqrt((m)/(k))rArrx_(m)=usqrt((m)/(k))` <br/> We obtain `x_(m)` = 2.00m</body></html>