Two bodies begin to fall freely from the same height. The second body begins to fall 'tau' s after the first. After what time from the beginning of first body dose the distance between the bodies equals to l?

Two bodies begin to fall freely from the same height. The second body

1.	Two bodies begin to fall freely from the same height. The second body begins to fall 'tau' s after the first. After what time from the beginning of first body dose the distance between the bodies equals to l?
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> the time of fall of the 1st <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> be t seconds Time of fall of second body `=t-tau` <br/> Distances of free fall of the bodies in the above time <a href="https://interviewquestions.tuteehub.com/tag/intervals-1049965" style="font-weight:bold;" target="_blank" title="Click to know more about INTERVALS">INTERVALS</a> respectively are <br/> `H_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=(gt^(2))/(2), H_(2)=(g(t-tau)^(2))/(2)` <br/> `H_(1)=(gt^(2))/(2), H_(2)=(g(t-tai)^(2))/(2)` <br/> Therefore `l=H_(i)-H_(2)=gt tau-1/2 gt^(2)""therefore t=l/(g tau)+tau /2`</body></html>