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Two capillary tubes of same radius `r` but of lengths `l_(1)` and `l_(2)` are fitted in parallel to the bottom of a vessel. The pressure to the bottom of a vessel. The pressure head is P. What should be the length of a singl tube of same radius that can replace the two tubes so that the rate of flow is same as before?A. `l_(1)+l_(2)`B. `(1)/(l_(1))+(1)/(l_(2))`C. `(l_(1)l_(2))/(l_(1)+l_(2))`D. `(1)/(l_(1)+l_(2))` |
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Answer» Correct Answer - C Fluid resistance `R=(8etaL)/(pir^(4))` in parallel `(1)/(R)=(1)/(R_(1))+(1)/(R_(2))` or `(pir^(4))/(8etal_(eq))=(pir^(4))/(8etal_(1))+(pir^(4))/(8etal_(2))` or `l_(eq)=(l_(1)l_(2))/(l_(1)+l_(2))` |
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