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Two circular rings of equal mass and radius are placed in such a way that their centres coincide but their planes are mutually perpendicular. Find the moment of inertia of the system when the system is rotated about the diameter of one of the rings.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :M.I of ring about its <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> `=MR^(2)` <br/> M.1 of a ring aout its <a href="https://interviewquestions.tuteehub.com/tag/diameter-950836" style="font-weight:bold;" target="_blank" title="Click to know more about DIAMETER">DIAMETER</a> `=(MR^(2))/(2)` <br/> `:.I=MR^(2)+(MR^(2))/(2)=(3MR^(2))/(2)`</body></html>


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