Two different dice are tossed together. Find the probability:(i) of ge

1.	Two different dice are tossed together. Find the probability:(i) of getting a doublet(ii) of getting a sum 10, of the numbers on the two dice.
Answer» 1)There are a total of 36 possibilities : { (1,1), (1,2), (1,3), (1,4), (1,5),(1,6) (2,1)(2,2)… …..(6,5) (6,6)} The doublets among these are (1,1), (2,2),(3,3)(4,4),(5,5),(6,6) So the probability of getting a doublet is : No. Of doublets / total no. of outcomes =6/36=1/6 2)Let B be the event of getting a sum of 10 of the numbers of two dice. n(B) = {6,4},{4,6},{5,5} = 3. Required probability P(B) = n(B)/n(S) = 3/36 = 1/12

Two different dice are tossed together. Find the probability:(i) of getting a doublet(ii) of getting a sum 10, of the numbers on the two dice.

Answer»

1)There are a total of 36 possibilities :

{ (1,1), (1,2), (1,3), (1,4), (1,5),(1,6) (2,1)(2,2)… …..(6,5) (6,6)}

The doublets among these are (1,1), (2,2),(3,3)(4,4),(5,5),(6,6)

So the probability of getting a doublet is :

No. Of doublets / total no. of outcomes =6/36=1/6

2)Let B be the event of getting a sum of 10 of the numbers of two dice.

n(B) = {6,4},{4,6},{5,5}

= 3.

Required probability P(B) = n(B)/n(S)

= 3/36

= 1/12