Two different dice are tossed together. Find the probability(i) of get

1.	Two different dice are tossed together. Find the probability(i) of getting a doublet(ii) of getting a sum 10, of the numbers on the two dice.
Answer» Given that two different dice are tossed. Total number of outcomes = 6^2 = 36. (1) Let A be the event of getting a doublet. n(A) = {1,1},{2,2},{3,3},{4,4},{5,5},{6,6} = 6. Required probability P(A) = 6/36 =1/6. (ii) Let B be the event of getting a sum of 10 of the numbers of two dice. n(B) = {6,4},{4,6},{5,5} = 3. Required probability P(B) = n(B)/n(S) = 3/36 =1/12

Two different dice are tossed together. Find the probability(i) of getting a doublet(ii) of getting a sum 10, of the numbers on the two dice.

Answer»

Given that two different dice are tossed.

Total number of outcomes = 6^2

= 36.

(1) Let A be the event of getting a doublet.

n(A) = {1,1},{2,2},{3,3},{4,4},{5,5},{6,6}

= 6.

Required probability P(A) = 6/36

=1/6.

(ii) Let B be the event of getting a sum of 10 of the numbers of two dice.

n(B) = {6,4},{4,6},{5,5}

= 3.

Required probability P(B) = n(B)/n(S)

= 3/36

=1/12