Two different dice are tossed together. Find the probability :(i) of g

1.	Two different dice are tossed together. Find the probability :(i) of getting a doublet(ii) of getting a sum 10, of the numbers on the two dice.
Answer» (i) Probability of getting a doublet when two different dice are tossed. then Total events n(S) = 6 x 5 = 36 Favourable events i.e., to getting doubtets E = {(1, 1), (2,2), (3,3), (4,4), (s,s), (6,6) n(E) = 6 Probability of getting a doubtets n(E) / n(s) = 6 / 36 = 1 / 6 Probability of getting a doublets = 1/ 6 (ii) Favourable events of getting a sum 10, of the numbers on the two dice E = {(4 , 6),(5,5),(6,4)} n(E) = 3 Probability of getting a sum 10, of the numbers on the two dice = n(E) / n(S) = 3 / 36 = 1 / 12

Two different dice are tossed together. Find the probability :(i) of getting a doublet(ii) of getting a sum 10, of the numbers on the two dice.

Answer»

(i) Probability of getting a doublet when two

different dice are tossed. then

Total events n(S) = 6 x 5 = 36

Favourable events i.e., to getting doubtets

E = {(1, 1), (2,2), (3,3), (4,4),

(s,s), (6,6)

n(E) = 6

Probability of getting a doubtets

n(E) / n(s) = 6 / 36 = 1 / 6

Probability of getting a doublets = 1/ 6

(ii) Favourable events of getting a sum 10, of the numbers on the two dice

E = {(4 , 6),(5,5),(6,4)}

n(E) = 3

Probability of getting a sum 10, of the numbers on the two dice = n(E) / n(S)

= 3 / 36 = 1 / 12

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