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Two equal circles of largest radii have following property: (i) They intersect each other orthogonally, (ii) They touch both the curves 4(y+2) = x^(2) and 4(2-y) =x^(2) in the region x in [-2 sqrt(2),2sqrt(2)]. Then radius of this circle is |
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Answer» `sqrt(2)` LET the RADIUS of CIRCLE is r. From geometry, `P -= (rsqrt(2),(r )/(sqrt(2)))`. Now, this point lies on the curve `4(2-y) =x^(2)` `rArr 4(2-(r )/(sqrt(2))) = (rsqrt(2))^(2)` `rArr r = sqrt(2)` |
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