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Two equal negative charges `-q` are fixed at points `(0, -a)` and `(0,a)` on y-axis. A poistive charge Q is released from rest at point `(2a, 0)` on the x-axis. The charge Q willA. execute simple harmonic motion about the origineB. move to the origin and remain at restC. move to infinityD. execute oscillatory but not simple harmonic motion. |
Answer» Correct Answer - D ` F_R =- 2F cos theta` ` F_R =- 2 (KQq.xa)/((x^2 +a^2)^(3//2))` Since ` x gt gt a`, so particel will excute oscillatory motion. |
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