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Two half cell reactions are given as : (i) `Fe_(aq)^(2+)+2e^(-) to Fe_((s)),E^(@)=-0.44" V "` (ii) `2H_((aq))^(+)+(1)/(2)O_(2)(g)+2e^(-) to H_(2)O(l),E^(@)=+1.23" V "` The `E^(@)` for the reaction `Fe_(s)+2H^(+)+(1)/(2)O_(2)(g) to Fe_(aq)^(2+)+H_(2)O_(l)` isA. `+1.67" V "`B. `-1.67" V "`C. `+0.79" V "`D. `-0.79" V "` |
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Answer» Correct Answer - A (a) Subtract equation (i) from equation (ii) to get equation (iii) `E^(@)=(+1.23)-(-0.44)=+1.67" V "`. |
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