InterviewSolution
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InterviewSolution
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Two identical current carrying coaxial loops, carry current I in an opposite sense. A simple amperian loop passes through both of them once. Calling the loop as C,A. `oint vecB.dvecl=+-2mu_0I`B. the value of `oint_CvecB.dvecl` is independent of sense of CC. there may be a point on C where `vecB` and `dvecl` are perpendicularD. `vecB` vanishes everywhere on C |
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Answer» Correct Answer - B::C Consider a simple amperian loop passing once through both the identical current carrying coaxial loops. (i) According to Ampere circuital law, `oint_CvecB.dvecl=mu_0(I-I)=0`. Hence, option (a) is wrong. (ii) As `oint_CvecB.dvecl=0`, therefore `oint_CvecB.dvecl` is independent of sense of C. Thus option (b) is correct. (iii) There will be a point on loop C, lying at the axis of two loops A and B, where `vecB` and `dvecl` are perpendicular to each other. Thus option(c) is correct. (iv) The value of `vecB` does not vanish on various points of C. Thus option (d) is wrong. |
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