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Two identical particles, each having a charge of `2.0xx10^(-4) C` and then released. What would be the speeds of the particles when the separtion becomes large? |
Answer» Correct Answer - `600 ms^(-1)` Here, `q = 2xx10^(-4)C, m = 10 g = 10^(-2) kg`, `r = 10 cm = 0.1m`. Let v , speed of each particle at infinite sepraration P.E. of two particles at the separationo of 10 cm. = K.E. of two particles at infinite separation `(1)/(4pi in_(0)) (q_(1) q_(2))/(r ) = (1)/(2) mv^(2) + (1)/(2) mv^(2)` `v^(2) = (1)/(4pi in_(0)) (q_(1) q_(2))/(r m) = (9xx10^(9)xx2xx10^(-4)xx2xx10^(-4))/(0.1xx10^(-2))` `= 36xx10^(4)` `v = 600 ms^(-1)` |
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