InterviewSolution
Saved Bookmarks
| 1. |
Two identical plane metallic surfaces A and B are kept parallel to each other in air separated by a distance of 1.0 cm as shown in fig. Surface A is given a positive potential of 10V and the outer surface of B is earthed. (i) What is the magnitude and direction of uniform electric field between points Y and Z ? (ii) What is work done in moving a charge of `20 muc` from point X to Y, where X is situated on surface A ? |
|
Answer» (i) Magnitude of electric field, `E = (dV)/(dr) = (10V)/(1xx10^(-2)m) = 10^(3) Vm^(-1)` The direction fo electric field is form Y to Z. (ii) As surface A is an equipotenital surface , therefore pot. Diff between X and Y is i..e, `DeltaV = 0` Work done `= q. DeltaV = 0`, i.e, no work is done is moving a charge from X to Y. |
|