Two limbs of a manometer consist of uniform capillary tubes of radii r_(1)andr_(2) respectively (r_(1)gtr_(2)). If the level of liquid in narrower tube stands at a height .h. above that in the broader tube then the exact pressure difference will be

Two limbs of a manometer consist of uniform capillary tubes of radii r

1.	Two limbs of a manometer consist of uniform capillary tubes of radii r_(1)andr_(2) respectively (r_(1)gtr_(2)). If the level of liquid in narrower tube stands at a height .h. above that in the broader tube then the exact pressure difference will be
Answer» <P> Solution :If `P_(1)andP_(2)` are the pressures in broader and NARROWER TUBES Then `P_(A)=P_(B)+hrhog` `P_(1)-(2S)/r_(1)=P_(2)-(2S)/r_(2)+HDG` `P_(1)-P_(2)=hrhog-2S[1/r_(2)-1/r_(1)]`