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Two objects of masses 4kg and 3kg are placed along X and T axes respectively at a distance of 1m from the origin. An object of mass 1kg is kept at the origin of the co-ordinatesystem. Calculate the resultant gravitational force attraction on the object at the origin. |
Answer» <html><body><p></p>Solution :Force due to 4kg mass on 1kg mass at the origin is <br/> `F_(1) = (G xx 4 xx 1)/(1^(2)) = 4G` <br/> Force due to 3kg mass on 1 kgmass at the origin is <br/> `F_(2) = (G xx 3 xx 1)/(1^(2)) = <a href="https://interviewquestions.tuteehub.com/tag/3g-310956" style="font-weight:bold;" target="_blank" title="Click to know more about 3G">3G</a>` <br/> The resultant force is found by <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> parallelo-gram law of vectors <br/> `F = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(F_(1)^(2) + F_(2)^(2) + 2F_(1)F_(2) cos theta)` <br/> `= sqrt((4G)^(2) + (3G)^(2) + 2(4g)(3G)cos <a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(@))= 5G` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_SLV_005_S01.png" width="80%"/></body></html> | |