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Two parallel forces P and Q (P gt Q) are acting at two points, A and B, of a body. If the forces interchange their positions, by how much will the point of action of the resultant of the resultant of the two forces shift along the line AB? |
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Answer» Solution :In Fig. SUPPOSE C is the point of ACTION of the resultant in the first case. `:. PxxAC=QxxBC""cdots(1)` If the NEW POSITION of the point of action of the resultant is C. then `QxxAC.=PxxBC. ""cdots(2)` From (1) we get, `PxxAC = Q(AB-AC) " ""or", (P+Q)xxAC=QxxAB` `:. AC=(Q)/(P+Q)xxAB` Similarly from (2) we get, `AC.=(P)/(P+Q)xxAB ""cdots(4)` `:.` Subtracting equation (3) from equation (4) we get, `AC. -AC =(AB)/((P+Q))(P-Q) " ""or", "CC".= (P-Q)/(P+Q) xxAB`.
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