1.

Two parallel forces P and Q (P gt Q) are acting at two points, A and B, of a body. If the forces interchange their positions, by how much will the point of action of the resultant of the resultant of the two forces shift along the line AB?

Answer»

Solution :In Fig. SUPPOSE C is the point of ACTION of the resultant in the first case.
`:. PxxAC=QxxBC""cdots(1)`
If the NEW POSITION of the point of action of the resultant is C. then
`QxxAC.=PxxBC. ""cdots(2)`
From (1) we get,
`PxxAC = Q(AB-AC) " ""or", (P+Q)xxAC=QxxAB`
`:. AC=(Q)/(P+Q)xxAB`
Similarly from (2) we get,
`AC.=(P)/(P+Q)xxAB ""cdots(4)`
`:.` Subtracting equation (3) from equation (4) we get,
`AC. -AC =(AB)/((P+Q))(P-Q) " ""or", "CC".= (P-Q)/(P+Q) xxAB`.


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