1.

Two parallel forces P and Q (P gt Q) are acting at two points, A and B, of a body. If the forces interchange their positions, by how much will the point of action of the resultant of the resultant of the two forces shift along the line AB?

Answer» <html><body><p></p>Solution :In Fig. <a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> C is the point of <a href="https://interviewquestions.tuteehub.com/tag/action-2544" style="font-weight:bold;" target="_blank" title="Click to know more about ACTION">ACTION</a> of the resultant in the first case. <br/> `:. PxxAC=QxxBC""cdots(1)` <br/> If the <a href="https://interviewquestions.tuteehub.com/tag/new-1114486" style="font-weight:bold;" target="_blank" title="Click to know more about NEW">NEW</a> <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> of the point of action of the resultant is C. then <br/> `QxxAC.=PxxBC. ""cdots(2)` <br/> From (1) we get, <br/> `PxxAC = Q(AB-AC) " ""or", (P+Q)xxAC=QxxAB` <br/> `:. AC=(Q)/(P+Q)xxAB` <br/> Similarly from (2) we get, <br/> `AC.=(P)/(P+Q)xxAB ""cdots(4)` <br/> `:.` Subtracting equation (<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) from equation (4) we get, <br/> `AC. -AC =(AB)/((P+Q))(P-Q) " ""or", "CC".= (P-Q)/(P+Q) xxAB`. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P1_U05_C01_SLV_019_S01.png" width="80%"/></body></html>


Discussion

No Comment Found

Related InterviewSolutions