Two particles are executing SHM in a straightline. Amplitude A and time period T of both the particles are equal. At time t=0, one particle is at displacement x_(1)=+A and the other at x_(2)=(-A)/23 and they are approaching towards each other. After what time they cross each other?

Two particles are executing SHM in a straightline. Amplitude A and tim

1.	Two particles are executing SHM in a straightline. Amplitude A and time period T of both the particles are equal. At time t=0, one particle is at displacement x_(1)=+A and the other at x_(2)=(-A)/23 and they are approaching towards each other. After what time they cross each other?
Answer» <html><body><p></p>Solution :Equation can be written as : `x_(1)=Acos omega t` and <br/> `x_(2)=<a href="https://interviewquestions.tuteehub.com/tag/asin-383934" style="font-weight:bold;" target="_blank" title="Click to know more about ASIN">ASIN</a>(omegat-pi//6)"" "Here" omega=(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/T` <br/> Equating `x_(1)=x_(2)""Sinx(omegat-(pi)/6)=<a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> omegat` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/sinomegat-3034688" style="font-weight:bold;" target="_blank" title="Click to know more about SINOMEGAT">SINOMEGAT</a>"cos"(pi)/6-"sin"(pi)/6cosomegast=cos omegat` <br/> `tan omega t=sqrt(3), omegat=(2pi)/T t=(pi)/3`, we get `t=T//6`</body></html>