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Two particles are moving with equal and opposite velocities in such a way that they are always at a constant distance apart. Calculate the time after which the particles return to their initial positions. |
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Answer» Clearly the two particles are at the two ends of the diameter of a circular path. It is further clear that each particle will return to its initial position after describing one circle. If t = required time then, t = \(\frac{2\pi r}{v}=\frac{\pi d}{v}\) Where, v = speed of particles. r = radius of the circular track d = constant distance between particles 2r = diameter of the circular path |
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