InterviewSolution
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InterviewSolution
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Two particles of equal mass have velocities `vec v_1 = 2 hat i= m//s^-1` and `vec v_2 = 2hat j m//s^-1`. First particle has an acceleration `vec a_1= (3 hat i+ 3 hat j) ms^-2` while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of.A. circleB. parabolaC. straight lineD. ellipse |
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Answer» Correct Answer - C ( c) `vec v_(cm) = (m 2 hat i+ m 2hat j)/(m + m) = hat i+ hat j m//s` `vec a_(cm) = (m(3 hat i+ 3 hat j)+m xx 0)/(m+m) = (3)/(2) hat i+ (3)/(2) hat j` Since acceleration and velocity are in same direction, so path should be straight line. |
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