Two point masses m1 and m2 are separated by a massless rod of length L. a) Write an expression for the moment of inertia about an axis perpendicular to the rod and passing through it at a distance X from mass m1 . Calculate d/dx and show that I is at a minimum when the axis passes through the center of mass of the system.

Two point masses m1 and m2 are separated by a massless rod of length L

1.	Two point masses m1 and m2 are separated by a massless rod of length L. a) Write an expression for the moment of inertia about an axis perpendicular to the rod and passing through it at a distance X from mass m1 . Calculate d/dx and show that I is at a minimum when the axis passes through the center of mass of the system.
Answer» <html><body><p>tion:we need to express the moment if inertia relative to the axis S <a href="https://interviewquestions.tuteehub.com/tag/passing-1148520" style="font-weight:bold;" target="_blank" title="Click to know more about PASSING">PASSING</a> through point O.The moment of inertia <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to a point mass m isIM= mr^2when m is the mass and r the <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> from the mass to the axis. In such fashion,the moment if <a href="https://interviewquestions.tuteehub.com/tag/m1-546405" style="font-weight:bold;" target="_blank" title="Click to know more about M1">M1</a> and m2 to S Total moment of inertia.I sist= i1+i2 finally the moment if interia of the rod and masses relative to S is,I sist=mx^2+m(L-x)^2</p></body></html>

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