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Two point masses m1 and m2 are separated by a massless rod of length L. a) Write an expression for the moment of inertia about an axis perpendicular to the rod and passing through it at a distance X from mass m1 . Calculate d/dx and show that I is at a minimum when the axis passes through the center of mass of the system. |
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Answer» tion:we need to express the moment if inertia relative to the axis S PASSING through point O.The moment of inertia DUE to a point mass m isIM= mr^2when m is the mass and r the DISTANCE from the mass to the axis. In such fashion,the moment if M1 and m2 to S Total moment of inertia.I sist= i1+i2 finally the moment if interia of the rod and masses relative to S is,I sist=mx^2+m(L-x)^2 |
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