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Two simple harmonic motions with the same frequency act on a particle at right angles i.e, along x and y axis. If the two amplitudes are equal and the phase difference is (pi)/(2) the resultant motion will be : |
Answer» <html><body><p>a circle<br/>an ellipse with the major axis along y-axis<br/>an ellipse with the major axis along y-axis<br/>an <a href="https://interviewquestions.tuteehub.com/tag/straight-633156" style="font-weight:bold;" target="_blank" title="Click to know more about STRAIGHT">STRAIGHT</a> line inclined at `45^(@)` to the x-axis </p>Solution :Equation of two simple harmonic motion <br/> `Y=A sin (<a href="https://interviewquestions.tuteehub.com/tag/omegat-2889234" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGAT">OMEGAT</a>+ phi) ""....(1)` <br/> `x= A sin (omega+phi+(pi)/(2))` <br/> `x=A cos (omegat+phi) ""....(2)`<br/> On squaring and adding <a href="https://interviewquestions.tuteehub.com/tag/equations-452536" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATIONS">EQUATIONS</a> (1) & (2)<br/>. `x^(2)+y^(2)=A^(2)` <br/> This is an equation of a circle. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, <a href="https://interviewquestions.tuteehub.com/tag/resulting-1187445" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTING">RESULTING</a> motion will be a circle motion.</body></html> | |