Two sitar strings A and B playing the note .Dha. are slightly out of tune and produce beats of frequency 5 Hz. The tension of the string B is slightly increased and the beat frequency is found to decrease to 3 Hz. What is the original frequency of B if the frequency of A is 427 Hz ?

Two sitar strings A and B playing the note .Dha. are slightly out of t

1.	Two sitar strings A and B playing the note .Dha. are slightly out of tune and produce beats of frequency 5 Hz. The tension of the string B is slightly increased and the beat frequency is found to decrease to 3 Hz. What is the original frequency of B if the frequency of A is 427 Hz ?
Answer» <html><body><p></p>Solution :Increase in the tension of a string increases its frequency. If the original frequency of B (`v_(B)`) were <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than that of A (`v_(A)`), further increase in `v_(B)` should have resulted in an increase in the <a href="https://interviewquestions.tuteehub.com/tag/beat-389944" style="font-weight:bold;" target="_blank" title="Click to know more about BEAT">BEAT</a> frequency. But the beat frequency is <a href="https://interviewquestions.tuteehub.com/tag/found-458144" style="font-weight:bold;" target="_blank" title="Click to know more about FOUND">FOUND</a> to decrease. this shows that `v_(B) lt v_(A)`. since `v_(A) - v_(B) = 5 Hz`, and `v_(A) = 427 Hz`, we get `v_(B) = 422 Hz`.</body></html>