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Two symmetrical dice are rolled. The probability that at least one of the two numbers is greater than 4 is |
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Answer» S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6),} n(S) = 36 Let Event A : At least one of the two is greater than 4. A = { (1,5), (1,6), (2,5), (2,6), (3,5), (3,6), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)} n (A) = 20 P(A) = n(A)/n(S) = 20/36 = 5/9 P(A) = 5/9 |
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