InterviewSolution
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InterviewSolution
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Two syringes of different cross-sections (without needles) filled with water are connected with a tightly fitted rubber tube filled with water. Diameters of the smaller piston and larger piston are 1.0cm and 3.0 cm respectively. (a) Find the force on the larger piston when a force of 10N is applied to the smaller piston. (b) The smaller piston is paused in through 6.0 cm, much does the larger piston move out? |
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Answer» (a). Since pressure is transmitted undiminished throughout the fluid, `F_(2)=(A_(2))/(A_(1))F_(1)=(pi(3//2xx10^(-2)m)^(2))/(pi(1//2xx10^(-2)m)^(2))xx10N` `=90N` (b). Water is considered to be perfectly incompressible. Volume covered by the movement of smaller piston inwards is equal to volume moved outwards due to the larger piston `L_(1)A_(1)=L_(2)A_(2)` `L_(2)=(A_(1))/(A_(2))L_(1)=(pi(1//2xx10^(-2)m)^(2))/(pi(3//2xx10^(-2)m)^(2))xx6xx10^(-2)m` `cong0.67xx10^(-2)m=0.67cm` Note, atmospheric pressure is common to both pistons and has been ignored. |
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