

InterviewSolution
Saved Bookmarks
1. |
Two trains `P` and `Q` are moving along parllel tracks same uniform speed of `20` m `s^(-1)`. The driver of train `P` decides to overtake train `Q` and accelerate his frain by `1 ms^(-2)`, After `50 s`, train `P` crosses the engine of train `Q`. Find out what was the distance between the two trains initially. provided the length each is `400 m`. |
Answer» Let the initial distance between two trains be `x`. Distance travelled by train `P` in `50 s`: `S_(p)=ut+(1)/(2)at^(2)=20xx50+(1)/(2)xx1xx50^(2)=2250 m` Distance travelled by train `Q` in `50` s: `S_(Q)=ut =20 xx50=100 m` Now `S_(P)-S_(Q) =2250-1000=1250 m`. This distance must be equal to the initial distance between the trains plus the sum of the length of the trains. `x+800 =1250 rArr x=450 m`. |
|