Upon heating `KClO_(3)` in the presence of catalytic amount of `MnO_(2)`, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure `HNO_(3)` gives Y and Z. W and X are, respectivelyA. `O_(2)andP_(4)O_(6)`B. `O_(2)andP_(4)O_(10)`C. `O_(3)andP_(4)O_(6)`D. `O_(3)andP_(4)O_(10)`

Upon heating `KClO_(3)` in the presence of catalytic amount of `MnO_(2

1.	Upon heating `KClO_(3)` in the presence of catalytic amount of `MnO_(2)`, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure `HNO_(3)` gives Y and Z. W and X are, respectivelyA. `O_(2)andP_(4)O_(6)`B. `O_(2)andP_(4)O_(10)`C. `O_(3)andP_(4)O_(6)`D. `O_(3)andP_(4)O_(10)`
Answer» Correct Answer - B `2KClO_(3)overset(MnO_(2),Delta)to2KCl+underset((W))(3O_(3))` `P_(4)+10O_(2)overset("Oxidation")tounderset((X))(P_(4)O_(10))` `P_(4)O_(10)` acts as dehydrating agent and removes `H_(2)O` from `HNO_(3)` to give `N_(2)O_(5)` (Y) and itself gets converted into `HPO_(3)` (Z). Thus, X is `P_(4)O_(10)` Y is `N_(2)O_(5)`, and Z in `HPO_(3)` and W is `O_(2)`. `P_(4)O_(10)+4HNO_(3)tounderset((Y))(2N_(2)O_(5))+underset((Z))(4HPO_(3))`

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