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Use the assumptions of the previous question. An object weighted by a spring balance at the equator gives the same reading as a reading taken at a depth d below the earth's surface at a pole (d lt lt R). The value of d is

Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>^(2) <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(2))/(g)`<br/>`(omega^(2) R^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>)`<br/>`(2omega^(2) R^(2))/(g)`<br/>`(sqrt(Rg))/(omega)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html>


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