InterviewSolution
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InterviewSolution
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Use the mirror equation to deduce that : d) an object placed between the pole and focus of a concave mirror produces a virtual and enlarged image. [Note : The exercise helps you deduce algebraically properties of images that one obtains from explicit ray diagrams.] |
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Answer» The mirror equation is `(1)/(u)+(1)/(v)=(1)/(f)` But `m=(upsilon)/(u)=(f)/(u-f)=(upsilon-f)/(f)` Hence `m=(f)/(u-f)` `upsilon =f(m+1)` d) When `u gt 0 lt f` we get `m=(f)/(u-f)=(f)/((gt 0 lt f)-f)=(f)/((gt -f lt 0))` `= gt -1` (`because` m is negative, image is virtual and enlarged because is numerically `y gt 1`). |
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